Answer:

x³+13x²+32x+20

by trial n error method

x(-1) = x³+13x²+32x+20

(-1)³+13(-1)²+32(-1)+20

-1+13-32+20

0

therefore, (x+1) is a factor

now, divided x³+13x²+32x+20 by (x+1)

= x²+12x+20

x²+12x+20

x²+10x+2x+20

x(x+10)+2(x+10)

(x+2)(x+10)

All the factors are :- (x+1)(x+2)(x+10)

hope it helps you...

┏━━━━━━━━━━━━━━━━━━━━━━━┓

_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ ✍️

Now,here we use hit and trial method by substituting values to make them 0

Now,putting x=-1 in the given polynomial

Hence,x+1 is a factor of the given polynomial.

we have to find another two roots ;for this divide the given polynomial by (x+1)

=>see in the picture for dividing process :-

After dividing we get x^2+ 12x+20(quotient) now we have to factorise the quotient to find other roots

Therefore,(x+1)(x+2)&(x+10) are the factors of the given polynomial

┗━━━━━━━━━━━━━━━━━━━━━━━┛