pa lagay din po ng solution thx
[tex] \} \frac{ab {}^{2} }{ab} [/tex]
[tex]\frac{x {}^{2} - 9}{x + 3} [/tex]
[tex] \frac{4x { }^{2 } - 8x + 12}{x - 3} [/tex]
[tex] \frac{x {}^{2} + 3x - 4 }{x {}^{3 } - 1} [/tex]
[tex] \} \frac{ab {}^{2} }{ab} [/tex]
[tex]\frac{x {}^{2} - 9}{x + 3} [/tex]
[tex] \frac{4x { }^{2 } - 8x + 12}{x - 3} [/tex]
[tex] \frac{x {}^{2} + 3x - 4 }{x {}^{3 } - 1} [/tex]
Answers & Comments
Answer:
x²-9 (x+3) (x-3)
___ = ________ = x-3
x+3 x+3
cancel the (x+3) in the numerator and denominator then write the remaining expression in the numerator for your final answer..
Step-by-step explanation: