[tex]\boxed{\text{If a , b , c are in AP then show that the given term is also in AP }} [/tex]
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[tex]\sf{a\bigg{(}\dfrac{1}{b} + \dfrac{1}{c} \bigg{)} \:,\: b\bigg{(} \dfrac{1}{c} + \dfrac{1}{a} \bigg{)} \:,\: c\bigg{(} \dfrac{1}{a} + \dfrac{1}{b} \bigg{)} } [/tex]

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