Transform each equations into quadratic equation :
[tex]1. \frac{2}{x + 1} + \frac{1}{2x} = \frac{x}{ {x}^{2} + 2x + 1 } \\ 2. \frac{a}{a + 3} - \frac{8}{a + 6} = 0 \\ 3. \frac{x + 1}{x - 3} - \frac{1}{x} = \frac{2}{x - 3} \\ 4. \frac{3x - 2}{x - 2} - \frac{6}{(x - 2)(x + 2)} = 1[/tex]
[tex]1. \frac{2}{x + 1} + \frac{1}{2x} = \frac{x}{ {x}^{2} + 2x + 1 } \\ 2. \frac{a}{a + 3} - \frac{8}{a + 6} = 0 \\ 3. \frac{x + 1}{x - 3} - \frac{1}{x} = \frac{2}{x - 3} \\ 4. \frac{3x - 2}{x - 2} - \frac{6}{(x - 2)(x + 2)} = 1[/tex]
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I don't have answer but I suggest to download an app for that PhotoMath kindly download that app so that you can answer your following module's in math
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Even if I don't have answer for that hope my suggestion can help:)