Given : ⁷²C₃₆
To Find : maximum possible exponent of 3
Solution:
⁷²C₃₆ = 72!/(36! 36!)
exponent of 3 in 72!
= [72/3¹] + [72/3²] + [72/3³] + [72/3⁴] +
= 24 + 8 + 2 + 0 + 0
= 34
exponent of 3 in 36!
= [36/3¹] + [36/3²] + [36/3³] + [36/3⁴] +
= 12 + 4 + 1 + 0
= 17
3³⁴/3¹⁷ * 3¹⁷
= 3³⁴/3³⁴
= 3⁰
Exponent of 3 is 0 in ⁷²C₃₆
Learn More:
It is desired to extract the maximum power of 3 from 24!, where n! = n
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brainly.in/question/11090581
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Given : ⁷²C₃₆
To Find : maximum possible exponent of 3
Solution:
⁷²C₃₆ = 72!/(36! 36!)
exponent of 3 in 72!
= [72/3¹] + [72/3²] + [72/3³] + [72/3⁴] +
= 24 + 8 + 2 + 0 + 0
= 34
exponent of 3 in 36!
= [36/3¹] + [36/3²] + [36/3³] + [36/3⁴] +
= 12 + 4 + 1 + 0
= 17
3³⁴/3¹⁷ * 3¹⁷
= 3³⁴/3³⁴
= 3⁰
Exponent of 3 is 0 in ⁷²C₃₆
Learn More:
It is desired to extract the maximum power of 3 from 24!, where n! = n
brainly.in/question/14760208
what is the highest power of 91 that divides 78! ? - Brainly.in
brainly.in/question/11090581