Questions


October 2022 1 14 Report
The area of the rectangle is
[tex] \frac{7 {x}^{5} }{21 {x}^{4} } [/tex]
If the length is
[tex] \frac{7 {x}^{3} }{3} [/tex]
what is its width?



Pick answer here --
A.
[tex] \frac{ {x}^{2} }{7 {x}^{4} } [/tex]
B.
[tex] \frac{ {x}^{8} }{63 {x}^{4} } [/tex]
C.
[tex] \frac{ {x}^{2} }{21 {x}^{3} } [/tex]
D.
[tex] \frac{1 {x}^{2} }{7 {x}^{3} } [/tex]


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