The area of the rectangle is
[tex] \frac{7 {x}^{5} }{21 {x}^{4} } [/tex]
If the length is
[tex] \frac{7 {x}^{3} }{3} [/tex]
what is its width?
Pick answer here --
A.
[tex] \frac{ {x}^{2} }{7 {x}^{4} } [/tex]
B.
[tex] \frac{ {x}^{8} }{63 {x}^{4} } [/tex]
C.
[tex] \frac{ {x}^{2} }{21 {x}^{3} } [/tex]
D.
[tex] \frac{1 {x}^{2} }{7 {x}^{3} } [/tex]
Answers & Comments
✏️![\frac{7x^5}{21x^4} + \frac{7x^3}{3} \frac{7x^5}{21x^4} + \frac{7x^3}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B7x%5E5%7D%7B21x%5E4%7D%20%2B%20%5Cfrac%7B7x%5E3%7D%7B3%7D)
SOLUTION STEPS
Cancel out
in both numerator and denominator.
the same denominator, add them by adding their numerators.
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