Rewrite the equation to standard form of the equation of a circle identify the center and radius:
[tex]3 {x }^{2} + 3 {y}^{2} + 4y - 7 = 0[/tex]
[tex]3 {x }^{2} + 3 {y}^{2} + 4y - 7 = 0[/tex]
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Step-by-step explanation:
x²+y²-4/3y+4/9=-7/3+4/9
(x)²+(y-2/3)²=-17/9
center is at (0,2/3) radius is(√-17/9) or (√-17)/3