B. Give the missing expression to make it a true statement.
[tex]1)if \: y - 3 > 4 \: then \: y - 3 + 3 > [/tex]
[tex]2)if \: \frac{x}{ - 3} \: \geqslant then \: \frac{x}{ - 3} ( - 3) \leqslant [/tex]
[tex]3)if \: 5x + 4 < - 6 \: then \: 5x + 4 - 4 < [/tex]
[tex]4)if \: \frac{x}{8} > - 3 \: then \: \frac{x}{8} (8) > [/tex]
[tex]5)if \: 4x \geqslant - 2 \: and \: - 2 \geqslant - 4 \: then \: 4x \geqslant [/tex]
[tex]1)if \: y - 3 > 4 \: then \: y - 3 + 3 > [/tex]
[tex]2)if \: \frac{x}{ - 3} \: \geqslant then \: \frac{x}{ - 3} ( - 3) \leqslant [/tex]
[tex]3)if \: 5x + 4 < - 6 \: then \: 5x + 4 - 4 < [/tex]
[tex]4)if \: \frac{x}{8} > - 3 \: then \: \frac{x}{8} (8) > [/tex]
[tex]5)if \: 4x \geqslant - 2 \: and \: - 2 \geqslant - 4 \: then \: 4x \geqslant [/tex]
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Answer:
1.)Originally Answered: What is 3+3x3-3+3=? To do it, you need to multiply 3 by 3 to get 9. Then you add 3 to 9 which gives you 12. Subtract 12 by 3 to get 9 then add 9 by 3 three to get 12, your answer.
Answer:12
2.(First we factor the denominators, then find a common denominator so we can subtract, then cross multiply and solve the resulting polynomial equation.
3
2
x
−
4
−
2
x
2
−
x
−
2
=
9
x
+
1
3
2
(
x
−
2
)
−
2
(
x
+
1
)
(
x
−
2
)
=
9
x
+
1
3
(
x
+
1
)
−
2
(
2
)
2
(
x
+
1
)
(
x
−
2
)
=
9
x
+
1
3
x
−
1
2
(
x
+
1
)
(
x
−
2
)
=
9
x
+
1
(
3
x
−
1
)
(
x
+
1
)
=
18
(
x
+
1
)
(
x
−
2
)
(
x
+
1
)
(
(
3
x
−
1
)
−
18
(
x
−
2
)
)
=
0
(
x
+
1
)
(
−
15
x
+
35
)
=
0
x
=
−
1
or
x
=
35
15
=
7
3
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