Answer:
There is a very interesting identity.
Let the numbers be x, y and z.
If x + y + z = 0; then x³ + y³ + z³ = 3xyz
Substitute.
Here,
Therefore,
⊱ ────── ✯ ────── ⊰
#CarryOnLearning
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Answers & Comments
Answer:
There is a very interesting identity.
Let the numbers be x, y and z.
If x + y + z = 0; then x³ + y³ + z³ = 3xyz
Substitute.
Here,![\sf e^{\pi}/3 > 1 \sf e^{\pi}/3 > 1](https://tex.z-dn.net/?f=%5Csf%20e%5E%7B%5Cpi%7D%2F3%20%3E%201)
Therefore,
⊱ ────── ✯ ────── ⊰
#CarryOnLearning