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Two resistances when connected in parallel give resultant value of 2 Ω, when connected in series the value becomes 9Ω. Calculate the value of each resistance.
Two resistances when connected in parallel give resultant value of 2 Ω, when connected in series the value becomes 9Ω. Calculate the value of each resistance.
Answers & Comments
Answer:
18
Explanation:
In parallel the resistance = 1/x + 1/y = 2
In series the resistance = x + y = 9
Lets keep y as x-9 --> 1
1/x + 1/x-9 = 2
x-9 + x/ x²-9x = 2
2x - 9 = 2x² - 18x
2x² - 20x + 9 = 0
x = 18