To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = p
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 0
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 04x^2 + kx - 75 = 0
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 04x^2 + kx - 75 = 0Now, we can rewrite the equation as a perfect square trinomial by adding and subtracting the square of half of the coefficient of x:
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 04x^2 + kx - 75 = 0Now, we can rewrite the equation as a perfect square trinomial by adding and subtracting the square of half of the coefficient of x:4x^2 + kx + (k/2)^2 - (k/2)^2 - 75 = 0
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 04x^2 + kx - 75 = 0Now, we can rewrite the equation as a perfect square trinomial by adding and subtracting the square of half of the coefficient of x:4x^2 + kx + (k/2)^2 - (k/2)^2 - 75 = 0This can be factored as:
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 04x^2 + kx - 75 = 0Now, we can rewrite the equation as a perfect square trinomial by adding and subtracting the square of half of the coefficient of x:4x^2 + kx + (k/2)^2 - (k/2)^2 - 75 = 0This can be factored as:(2x + k/2)^2 - (k^2/4) - 75 = 0
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 04x^2 + kx - 75 = 0Now, we can rewrite the equation as a perfect square trinomial by adding and subtracting the square of half of the coefficient of x:4x^2 + kx + (k/2)^2 - (k/2)^2 - 75 = 0This can be factored as:(2x + k/2)^2 - (k^2/4) - 75 = 0To make it a perfect square trinomial, we need to have (k^2/4) + 75 = 0, which means:
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 04x^2 + kx - 75 = 0Now, we can rewrite the equation as a perfect square trinomial by adding and subtracting the square of half of the coefficient of x:4x^2 + kx + (k/2)^2 - (k/2)^2 - 75 = 0This can be factored as:(2x + k/2)^2 - (k^2/4) - 75 = 0To make it a perfect square trinomial, we need to have (k^2/4) + 75 = 0, which means:k^2/4 = -75
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 04x^2 + kx - 75 = 0Now, we can rewrite the equation as a perfect square trinomial by adding and subtracting the square of half of the coefficient of x:4x^2 + kx + (k/2)^2 - (k/2)^2 - 75 = 0This can be factored as:(2x + k/2)^2 - (k^2/4) - 75 = 0To make it a perfect square trinomial, we need to have (k^2/4) + 75 = 0, which means:k^2/4 = -75k^2 = -300
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 04x^2 + kx - 75 = 0Now, we can rewrite the equation as a perfect square trinomial by adding and subtracting the square of half of the coefficient of x:4x^2 + kx + (k/2)^2 - (k/2)^2 - 75 = 0This can be factored as:(2x + k/2)^2 - (k^2/4) - 75 = 0To make it a perfect square trinomial, we need to have (k^2/4) + 75 = 0, which means:k^2/4 = -75k^2 = -300Since a square cannot be negative, there is no real value of k that allows the quadratic equation to be solved by extracting the square root.
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To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = p
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 0
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 04x^2 + kx - 75 = 0
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 04x^2 + kx - 75 = 0Now, we can rewrite the equation as a perfect square trinomial by adding and subtracting the square of half of the coefficient of x:
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 04x^2 + kx - 75 = 0Now, we can rewrite the equation as a perfect square trinomial by adding and subtracting the square of half of the coefficient of x:4x^2 + kx + (k/2)^2 - (k/2)^2 - 75 = 0
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 04x^2 + kx - 75 = 0Now, we can rewrite the equation as a perfect square trinomial by adding and subtracting the square of half of the coefficient of x:4x^2 + kx + (k/2)^2 - (k/2)^2 - 75 = 0This can be factored as:
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 04x^2 + kx - 75 = 0Now, we can rewrite the equation as a perfect square trinomial by adding and subtracting the square of half of the coefficient of x:4x^2 + kx + (k/2)^2 - (k/2)^2 - 75 = 0This can be factored as:(2x + k/2)^2 - (k^2/4) - 75 = 0
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 04x^2 + kx - 75 = 0Now, we can rewrite the equation as a perfect square trinomial by adding and subtracting the square of half of the coefficient of x:4x^2 + kx + (k/2)^2 - (k/2)^2 - 75 = 0This can be factored as:(2x + k/2)^2 - (k^2/4) - 75 = 0To make it a perfect square trinomial, we need to have (k^2/4) + 75 = 0, which means:
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 04x^2 + kx - 75 = 0Now, we can rewrite the equation as a perfect square trinomial by adding and subtracting the square of half of the coefficient of x:4x^2 + kx + (k/2)^2 - (k/2)^2 - 75 = 0This can be factored as:(2x + k/2)^2 - (k^2/4) - 75 = 0To make it a perfect square trinomial, we need to have (k^2/4) + 75 = 0, which means:k^2/4 = -75
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 04x^2 + kx - 75 = 0Now, we can rewrite the equation as a perfect square trinomial by adding and subtracting the square of half of the coefficient of x:4x^2 + kx + (k/2)^2 - (k/2)^2 - 75 = 0This can be factored as:(2x + k/2)^2 - (k^2/4) - 75 = 0To make it a perfect square trinomial, we need to have (k^2/4) + 75 = 0, which means:k^2/4 = -75k^2 = -300
To solve the quadratic equation 4x^2 + kx + 25 = 100 by extracting the square root we need to rewrite it in the form (x - h)^2 = pFirst, let's subtract 100 from both sides of the equation to get:4x^2 + kx + 25 - 100 = 04x^2 + kx - 75 = 0Now, we can rewrite the equation as a perfect square trinomial by adding and subtracting the square of half of the coefficient of x:4x^2 + kx + (k/2)^2 - (k/2)^2 - 75 = 0This can be factored as:(2x + k/2)^2 - (k^2/4) - 75 = 0To make it a perfect square trinomial, we need to have (k^2/4) + 75 = 0, which means:k^2/4 = -75k^2 = -300Since a square cannot be negative, there is no real value of k that allows the quadratic equation to be solved by extracting the square root.