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Factorise :
[tex] ( {x}^{2} + \frac{1}{{x}^{2}} ) - 4(x + \frac{1}{x} ) + 6 [/tex]
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Factorise :
[tex] ( {x}^{2} + \frac{1}{{x}^{2}} ) - 4(x + \frac{1}{x} ) + 6 [/tex]
✔Solution Must
❌No spamming
Have Great future ahead!
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= > x^2 +\frac{1}{x^2} - 2x - 2x -\frac{2}{x} -\frac{2}{x} + 1 + 1 + 4=>x2+x21−2x−2x−x2−x2+1+1+4
= > x^2 + 1 - 2x + 1 + \frac{1}{x^2} -\frac{2}{x} - 2x -\frac{2}{x} + 4=>x2+1−2x+1+x21−x2−2x−x2+4
= > x(x +\frac{1}{x} - 2) +\frac{1}{x}(x +\frac{1}{x} - 2) - 2(x +\frac{1}{x} - 2)=>x(x+x1−2)+x1(x+x1−2)−2(x+x1−2)
= > (x +\frac{1}{x} - 2)(x +\frac{1}{x} - 2)=>(x+x1−2)(x+x1−2)
= > (x +\frac{1}{x} - 2)^2=>(x+x1−2)2