Perform the indicated operations
1.
[tex] \sqrt{12} + \sqrt{12} = [/tex]
2.
[tex] \sqrt{2} - 3 \sqrt{32} = [/tex]
3.
[tex] \sqrt{32} \div \sqrt{8} = [/tex]
Pashagot
1.
[tex] \sqrt{12} + \sqrt{12} = [/tex]
2.
[tex] \sqrt{2} - 3 \sqrt{32} = [/tex]
3.
[tex] \sqrt{32} \div \sqrt{8} = [/tex]
Pashagot
Add an Answer
More Questions From This User See All
Answers & Comments
d kpo alam sorry
eheheehehhehe
Answer:
sorry po hindi ko po alam eh read ka nlng po <3