The value of [tex](1+i)^{2n}+(1-i)^{2n}\:\&\:(n\:\in\:N)[/tex] is zero if-
(a) n is odd
(b) n is multiple of 4
(c) n is even
(d) [tex]\frac{n}{2}[/tex] is odd
(a) n is odd
(b) n is multiple of 4
(c) n is even
(d) [tex]\frac{n}{2}[/tex] is odd
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Answer:
Step-by-step explanation:
Complex numbers:-
Given an equation,in which we have to find the nature of n.
Taking square of terms in bracket,we get an expression.
(2i)^n+(-2i)^n=0
Since,i^n can't be 0
Hence,we find 2^n+(-2)^n=0, satisfying only for odd values of n(1,3,5,...)
So, option A is correct.
Answer:
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Step-by-step explanation:
mark as a brainlist answer.