If
[tex] log_{2}[/tex]
y = x and
[tex] log_{ 3}[/tex]
z = x, find
[tex]72 ^{x} [/tex]
in terms of y and z
(please give steb by step explaination for this)
[tex] log_{2}[/tex]
y = x and
[tex] log_{ 3}[/tex]
z = x, find
[tex]72 ^{x} [/tex]
in terms of y and z
(please give steb by step explaination for this)
Answers & Comments
Answer:
Solution
verified
Verified by Toppr
Given:
log
2
y=x
2
x
=y
log
3
z=x
3
x
=z
So,
72
x
=(2×2×2×3×3)
x
=(2
3
×3
2
)
x
=(2
x
)
3
×(3
x
)
2
=y
3
×z
2
=y
3
z
2
Step-by-step explanation:
Solution
verified
Verified by Toppr
Given:
log
2
y=x
2
x
=y
log
3
z=x
3
x
=z
So,
72
x
=(2×2×2×3×3)
x
=(2
3
×3
2
)
x
=(2
x
)
3
×(3
x
)
2
=y
3
×z
2
=y
3
z