Suman split a bag of chocolates amongst four children. Payal got
[tex] \frac{7}{15} [/tex]
, Shubh got
[tex] \frac{7}{8} [/tex]
. Raj got
[tex] \frac{7}{20} [/tex]
and Lata got
[tex] \frac{7}{10} [/tex]
. Arrange the names of the children in the order who got from least to greatest number of chocolates.
EXPLAIN and explain fr class 6
[tex] \frac{7}{15} [/tex]
, Shubh got
[tex] \frac{7}{8} [/tex]
. Raj got
[tex] \frac{7}{20} [/tex]
and Lata got
[tex] \frac{7}{10} [/tex]
. Arrange the names of the children in the order who got from least to greatest number of chocolates.
EXPLAIN and explain fr class 6
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Answer:
1. Shubh
2.Lata
3.Payal
4.Raj
Step-by-step explanation:
Given : payal got 7/15 , Shubh got 7/8 , Raj got 7/20 and lata got 7/10
Here we will take the lcm of all of these
56 , 105 , 42 , 84
--------------------------
120
Hence , Payal = 56/120
Shubh = 105 /120
Raj = 42/120
Lata = 84/120
In order to from least to the greatest :
Raj<payal<lata<Shubh
Hope it helps you !!!