Using bodmas pls solve this problem for me
2×(0)²×(-1) + 2(0)×(-1) + 0×(-1)
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[tex] \leqslant \geqslant [/tex]
2×(0)²×(-1) + 2(0)×(-1) + 0×(-1)
DO NOT SPAM !
[tex] \leqslant \geqslant [/tex]
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Verified answer
Answer:
Certainly, let's solve the expression following the order of operations (BODMAS/BIDMAS):
\[ 2 \times (0)^2 \times (-1) + 2 \times (0) \times (-1) + 0 \times (-1) \]
First, calculate the squares:
\[ 2 \times 0 \times (-1) + 2 \times 0 \times (-1) + 0 \times (-1) \]
Now, multiply:
\[ 0 + 0 + 0 \]
The result is \(0\).
Answer:
0
Step-by-step explanation:
0 is the answer by bodmas