[tex] \huge \mathbb \red{QuEsTiOn :}[/tex]
If Red colour ( wave length=7500 A) N numbe's bright Fringe and green colour's (wave length=6000 A) (N+1) numbe's bright Fringe are overlapping, so the value of
n = ..............
(A) 2
(B) 3
(C) 4
(D) 5
[tex] \sf \pink{Answer \: With \: Full \: Explanation. }[/tex]
If Red colour ( wave length=7500 A) N numbe's bright Fringe and green colour's (wave length=6000 A) (N+1) numbe's bright Fringe are overlapping, so the value of
n = ..............
(A) 2
(B) 3
(C) 4
(D) 5
[tex] \sf \pink{Answer \: With \: Full \: Explanation. }[/tex]
Answers & Comments
Answer:
4 option c
Explanation:
Sorry but I am some where'as week in Trongy maths type questions...!
Verified answer
[tex]\huge{ \texttt{ \color{Navy}{αηѕωєя}}}[/tex]
[tex]{ \small{ \textsf{ \color{purple}Since, the two bright fringes coincide}}}[/tex]
[tex]{ \color{teal}∴ηλ{\tiny{1}}=(n + 1)λ\tiny2}[/tex]
[tex]{ \color{teal}or \: \frac{n+1}{n}= \frac{λ \tiny1}{λ \tiny2} = \frac{7500}{60000} = \frac{5}{4} }[/tex]
[tex]{ \color{teal}or \: 1 + \frac{1}{n} = \frac{5}{4}⇒n = 4}[/tex]
[tex]{\textbf{\color{pink}(c) 4}}[/tex]