Simplify this:-
[tex]\frac { ( \frac { 2 } { 5 } ) x ^ { - 2 } \times 3 y ^ { 2 } ( y + x ^ { 2 } ) } { x ^ { 3 } \times y ^ { 3 } }[/tex]
[tex]\frac { ( \frac { 2 } { 5 } ) x ^ { - 2 } \times 3 y ^ { 2 } ( y + x ^ { 2 } ) } { x ^ { 3 } \times y ^ { 3 } }[/tex]
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Answer:
For x = 2 and y = - 3 , verify the following: (x - y)^2 = x^2 - 2xy + y^2
Missing: x2x3y²( | Must include: x2x3y²(
Top answer · 20 votes
Given equation is, (x - y)^2 = x^2 - 2xy + y^2 For x = 2 and y = - 3 LHS = (x - y)^2 = (2 - ( - 3))^2 = (2 + 3)^2 = (5)^2 = 25 RHS = x^2 - 2xy + y^2 = (2)^2
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