Step-by-step explanation:

x^3 + 6x^2 + 9x + 3 , x-1

p ( x ) = x^3 + 6x^2 + 9x + 3

x- 1 = 0

x = 1

p ( x ) = x^3 + 6x^2 +9x + 3

put x = 1

p ( 1 ) = ( 1 )^3 + 6 ( 1 )^2 + 9 ( 1 ) + 3

p ( 1 ) = 1 + 6 + 9 + 3

p ( 1 ) = 19

by remainder thm

remainder is 19