[tex]⟹∠AOC + ∠BOC - 180°[/tex]

[tex]⟹∠AOC+65°-180°[/tex]

[tex]⟹∠AOC =180°-65°[/tex]

[tex]⟹∠AOC=115°[/tex]

[tex]⟹∠AOC=2∠CDB[/tex]

[tex]⟹115°=2∠CDB[/tex]

[tex]⟹∠CDB = 115°×2[/tex]

[tex]⟹∠CDB = 230°[/tex]

Verified answer

Correct answer:-

⟹∠AOC+∠BOC−180°

⟹∠AOC+65°-180°⟹∠AOC+65°−180°

⟹∠AOC =180°-65°⟹∠AOC=180°−65°

⟹∠AOC=115°⟹∠AOC=115°

⟹∠AOC=2∠CDB⟹∠AOC=2∠CDB

⟹115°=2∠CDB⟹115°=2∠CDB

⟹∠CDB = 115°×2⟹∠CDB=115°×2

⟹∠CDB = 230°⟹∠CDB=230°

Final answer:-

option (a) 230°

hope it helps ♡

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