Step-by-step explanation:
Given
a = 3, b = - 2, c = - 1
To be verified
b × ( a + c) = b × a + b × c
Substitute the given values in the equation
⇒ - 2 ( 3 - 1 ) = - 2( 3 ) - 2( - 1 )
⇒ - 2( 2 ) = - 6 + 2
⇒ - 4 = - 4
LHS = RHS
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Answers & Comments
Verified answer
[tex]a= 3 \: , \: b= -2 \: , \: c = -1[/tex]
[tex]b \times (a + c) = (b \times a) + (b \times c)[/tex]
[tex]-2 × [(3 + (-1) ] = [( - 2) \times 3 ] + [( - 2) \times ( - 1) ] [/tex]
[tex] - 2 \times (3 - 1) = ( - 6) + (2)[/tex]
[tex] - 2 \times 2 = - 6 + 2[/tex]
[tex] - 4 = - 4[/tex]
[tex]LH.S = R.H.S[/tex]
Distributive Property
Step-by-step explanation:
Given
a = 3, b = - 2, c = - 1
To be verified
b × ( a + c) = b × a + b × c
Substitute the given values in the equation
⇒ - 2 ( 3 - 1 ) = - 2( 3 ) - 2( - 1 )
⇒ - 2( 2 ) = - 6 + 2
⇒ - 4 = - 4
LHS = RHS
Hence verified