hope it helps
pls mark as brainliest
Step-by-step explanation:
1-i/1+i=u+iv
1-i*1-i/1+i*1-i=u+iv
1-i*1-i/(1^2-i^2)=u+iv
1-1i-i1+i/(1^2-i^2)=u+iv
1-1i+i
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Answers & Comments
hope it helps
pls mark as brainliest
Step-by-step explanation:
1-i/1+i=u+iv
1-i*1-i/1+i*1-i=u+iv
1-i*1-i/(1^2-i^2)=u+iv
1-1i-i1+i/(1^2-i^2)=u+iv
1-1i+i