Verified answer

Given:

Distance between Sanna's and Sneha's house is 9km. Sanna has to attend Sneha's birthday party at 7 o'clock. She started from her home at 6 o'clock on her bicycle and covered a distance of 6km in 40 mins. At the point she meet Micky and spoke to her for 5 mins and reached Sneha's birthday party at 7 o'clock.

To find:

With what speed did she cover the second part of the journey? Calculate his average speed for the entire journey.

Concept:

If a person has a average speed along the course of the journey, its motion can be understood by calculating average speed. Average speed by the person can be calculated by using the following formula:

[tex]\;\;\boxed{\:\textbf{\textsf{Average Speed = }} \dfrac{\textbf{\textsf{Total Distance}}}{\textbf{\textsf{Total Time\:}}}} [/tex]

This implies "Average speed is the ratio of total distance and total time taken to cover the distance."

Calculations:

Distance left to reach Sneha's house = 9km - 6km = 3km

And, Time left to reach Sneha's house = 16 min - (4 + 5) = 15 minutes

• Distance left = 3km

• Time left = 15 mins

The speed with which Sanna covered the second part of the journey:

[tex]\rm{\implies\dfrac{Distance\;left\;to\;reach\;Sneha's\;house}{Time\;left\;to\;reach\;Sneha's\;house}}

[/tex]

[tex]\rm{\implies\dfrac{3}{15}}[/tex]

[tex]\rm{\implies 0.2}⟹0.2[/tex]

Thus, the speed with which Sanna covered the second part of the journey is 0.2km/h.

We know that,

[tex]\rm{\implies Average\;Speed=\dfrac{Total\; Distance}{Total\;Time}}

[/tex]

• Total distance = 9km

• Total time = 1 hour

By substituting the given values in the formula, we get the following results:

[tex]\rm{\implies Average\;Speed=\dfrac{9}{1}}[/tex]

[tex]\rm{\implies \boxed{\textsf{\textbf{ Average Speed = 9 km/h }}}}[/tex]

\rule{300}{2}

Hence, the average speed of the entire journey is 9km/h.

Extra Information:

Average velocity is the displacement of an object over time. It is calculated by using the following formula:

[tex]\;\;\boxed{\:\textbf{\textsf{Average Velocity = }} \dfrac{\textbf{\textsf{Total Displacement}}}{\textbf{\textsf{Total Time\:}}}} [/tex]

This implies "Average velocity the change in position or displacement (Δx) divided by the change in time or time intervals (Δt)."

Answer:

Party start at 7’o clock

Total time spend by Bholu = 40 min (traveling) + 5 min (chatting) = 45 min

So Bholu has to reach Golu’s house within 15 min (1hour – 45 min)

The speed with which Bholu has to cover the second part of the journey is= 3/15 Km/min=12 Km/h

Average The average of Bholu’s in the entire journey is total distance divided by total the time taken is

=Total distance traveled / total time taken

=9Km/h

Thankeww For Thanks ❤✨

[tex]\huge\mathtt{\pink{Ⲧ}\purple{ⲇ}\blue{ꪜ}\red{ⳙ}\green{ⳙ}}\:\huge\mathtt{\orange{♡}}[/tex]