Verified answer

Answer:

Given y=2(a−x)(x+x2+b2)          (1)

Put x+x2+b2=t

∴x2+b2=t−x

Squaring both sides, we get,

x2+b2=(t−x)2

∴x2+b2=t2−2tx+x2

∴b2=t2−2tx

∴2tx=t2−b2

∴x=2tt2−b2

Thus, from equation (1),

y=2(a−2tt2−b2)t