Answer:

[tex] \bold{3 {x}^{2} - 5x + 2 = 0}[/tex]

Apply quadratic formula--

[tex] \red{d = {b}^{2} - 4ac}[/tex]

[tex] = {5}^{2} - 4(3)(2)[/tex]

[tex] = 25 - 24[/tex]

[tex] = 1[/tex]

Now,

[tex] \green{x = \frac{ - b \: - + \sqrt{d} }{2a} }[/tex]

[tex]x = \frac{5 - + 1}{6} [/tex]

So,

[tex] \orange {x = 1} \: \blue{and} \: \pink{x = \frac{2}{3} }[/tex]

Plz thanks and mark brainliest

Verified answer

[tex]\colorbox{green}{★ANSWER ★}[/tex]

[tex]3 {x}^{2} - 5x + 2 = 0[/tex]

Here, A=3,B=–5,C=2

[tex]then, {b}^{2} - 4ac = ( - 5)^{2} - 4(3)(2) = 25 - 24 = 1 > 0[/tex]

[tex]x = \frac{ - b + \sqrt{b}^{2} - 4ac }{2a} [/tex]

[tex] = \frac{5 + \sqrt{1} }{2(3)} [/tex]

[tex] = \frac{5 + \sqrt{1} }{6} [/tex]

[tex] = \frac{5 + 1}{6} [/tex]

[tex]i.e., \: x = 1 \: or \: x = \frac{2}{3} [/tex]

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[tex]1 \: and \: \frac{2}{3} [/tex]