sin3/5
cos4/5
tan theta =sin theta/cos theta
tan A=3/4
Step-by-step explanation:
[tex] \bold{Given \: that,}[/tex]
[tex] \sf \: sin = \frac{3}{5} \\ \sf \: cos = \frac{4}{5} [/tex]
we know that,
[tex] \sf \: tan= \frac{opposite}{adjacent} \\ \sf \: \tan = \frac{sin}{cos}[/tex]
Now,
[tex] \sf \: tan = \frac{ \frac{3}{5} }{ \frac{4}{5} } \\ \sf \: so \: tan= \frac{3}{4} [/tex]
______________________________
[tex] \bf \purple{cosine \: and \: tangent \: formulas,} \\ \sf \: sin= \frac{opposite}{hypotenuse} \\ \\ \sf cos= \frac{adjacent}{hypotenuse} \\ \\ \sf \: tan= \frac{opposite}{adjacent} [/tex]
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Answers & Comments
sin3/5
cos4/5
tan theta =sin theta/cos theta
tan A=3/4
Verified answer
Step-by-step explanation:
[tex] \bold{Given \: that,}[/tex]
[tex] \sf \: sin = \frac{3}{5} \\ \sf \: cos = \frac{4}{5} [/tex]
we know that,
[tex] \sf \: tan= \frac{opposite}{adjacent} \\ \sf \: \tan = \frac{sin}{cos}[/tex]
Now,
[tex] \sf \: tan = \frac{ \frac{3}{5} }{ \frac{4}{5} } \\ \sf \: so \: tan= \frac{3}{4} [/tex]
______________________________
[tex] \bf \purple{cosine \: and \: tangent \: formulas,} \\ \sf \: sin= \frac{opposite}{hypotenuse} \\ \\ \sf cos= \frac{adjacent}{hypotenuse} \\ \\ \sf \: tan= \frac{opposite}{adjacent} [/tex]