[tex]\begin{gathered} \\ \large{ \dashrightarrow{ \underline{ \underline{ \pmb{ \rm{ \: Qᴜᴇsᴛɪᴏɴ: - \: }}}}}} \\ \\ \end{gathered}[/tex]
࿐ Eᴠᴀʟᴜᴀᴛᴇ ᴛʜɪs :
[tex]\begin{gathered} \\ \: \bf{sɪɴ60°ᴄᴏs30°+sɪɴ30°ᴄᴏs60°} \\ \\ \end{gathered}[/tex]
[tex]\rule{220pt}{4pt}[/tex]
[tex]\begin{gathered} \\ \longmapsto{ \displaystyle{\bf{ \mathsf{ \: Answer \: Only \: Moderators \: and \: Great \: Users.}}}} \\ \\ \end{gathered}[/tex]
[tex]\begin{gathered} \\ \longmapsto{ \displaystyle{ \bf{ \mathsf{ \: No \: Spamming \: will \: be \: allowed.}}}} \\ \\ \end{gathered}[/tex]
[tex]\begin{gathered} \\ \longmapsto{ \displaystyle{ \bf{ \mathsf{ \: Use \: latex \: for \: your \: Answer.}}}} \\ \\ \end{gathered}[/tex]
[tex]\begin{gathered} \\ \longmapsto{ \displaystyle{ \bf{ \mathsf{ \: ✯ \: Best \: of \: Luck✯.}}}} \\ \\ \end{gathered}[/tex]
[tex]\rule{220pt}{4pt}[/tex]
Answers & Comments
Answer:
[tex] \boxed{ \star \blue{ \large\underline{ \huge \sf \pink{hello \: pooja \: }}}}[/tex]
Given that:-
[tex]\begin{gathered} \\ \: \bf{sɪɴ60°ᴄᴏs30°+sɪɴ30°ᴄᴏs60°} \\ \\ \end{gathered}[/tex]
To find:-
Evaluation
Quick tip:-
Trigonometry values for angles 0°, 30°, 45°, 60°and 90°, with respect to sin, cos, tan, cot, sec, cosec functions, taking an example of the right-angle triangle.
Have a look at the table in the attachment
We know that,
[tex] \sin60 \degree = \frac{ \sqrt{3} }{2} \\ [/tex]
[tex] \cos30 \degree = \frac{ \sqrt{3} }{2} \\ \\ \sin 30\degree = \frac{1}{2} \\ \\ \cos60 \degree = \frac{1}{2} [/tex]
Putting all values
[tex]\begin{gathered} \\ \: \bf{sɪɴ60°ᴄᴏs30°+sɪɴ30°ᴄᴏs60°} \\ \\ \end{gathered}[/tex]
[tex] = ( \frac{ \sqrt{3} }{2} ) \times ( \frac{ \sqrt{3} }{2} ) \times ( \frac{1}{2} ) \times ( \frac{1}{2} )[/tex]
[tex] = \frac{ \sqrt{3} \times \sqrt{3} }{2 \times 2} + \frac{1}{2 \times 2} \\ [/tex]
[tex] = \frac{3}{4} + \frac{1}{4} \\ \\ = \frac{3 \ + 1}{4} \\ \\ = \frac{ \cancel4}{ \cancel4} \\ \\ = 1[/tex]
[tex]\begin{gathered} \\ \: \bf{sɪɴ60°ᴄᴏs30°+sɪɴ30°ᴄᴏs60°} = 1\\ \\ \end{gathered}[/tex]
Hope it helps you from my side!!
Keep Learning!!
[tex] \huge\star \: \rule{200pt}{2.5pt}[/tex]
Verified answer
Given :
[tex] \\ \\ [/tex]
To Find :
[tex] \\ \\ \qquad{\rule{200pt}{2pt}} [/tex]
SolutioN :
[tex] \dag \; {\underline{\underline{\sf{ \; Here \; we \; have \; :- }}}} [/tex]
[tex] \; \; {\longrightarrow \; {\underline{\boxed{\red{\sf{ Sin \; 60^{ \circ } = \dfrac{ \sqrt{3} }{2} }}}}}} \; \; \; \; \; \; \; {\longrightarrow \; {\underline{\boxed{\purple{\sf{ Cos \; 30^{ \circ } = \dfrac{ \sqrt{3} }{2} }}}}}} [/tex]
[tex] \\ [/tex]
[tex] \; \; {\longrightarrow \; {\underline{\boxed{\orange{\sf{ Sin \; 30^{ \circ } = \dfrac{ 1 }{2} }}}}}} \; \; \; \; \; \; \; \; \; {\longrightarrow \; {\underline{\boxed{\green{\sf{ Cos \; 60^{ \circ } = \dfrac{ 1 }{2} }}}}}} [/tex]
[tex] \\ \\ [/tex]
[tex] \dag \; {\underline{\underline{\sf{ \; Calculating \; the \; Value \; :- }}}} [/tex]
[tex] \; \; :\implies \; \sf { Sin 60^{ \circ } Cos 30^{ \circ } + Sin 30^{ \circ } Cos 60^{ \circ } } \\ \\ [/tex]
[tex] \; \; :\implies \; \sf { \bigg\lgroup \dfrac{ \sqrt{3} }{2} \times \dfrac{ \sqrt{3} }{2} \bigg\rgroup + \bigg\lgroup \dfrac{1}{2} \times \dfrac{1}{2} \bigg\rgroup } \\ \\ [/tex]
[tex] \; \; :\implies \; \sf { \dfrac{3}{4} + \dfrac{1}{4} } \\ \\ [/tex]
[tex] \; \; :\implies \; \sf { \dfrac{3 + 1}{4} } \\ \\ [/tex]
[tex] \; \; :\implies \; \sf { \dfrac{4}{4} } \\ \\ [/tex]
[tex] \; \; :\implies \; \sf { \cancel\dfrac{4}{4} } \\ \\ [/tex]
[tex] \; \; :\implies \; {\pmb{\underline{\boxed{\pink{\frak { 1 }}}}}} \; \bigstar \\ \\ [/tex]
[tex] \\ \\ [/tex]
[tex] \qquad \; \therefore \; [/tex] Value of the given Equation is 1
[tex] \\ {\underline{\rule{300pt}{9pt}}} [/tex]
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