[tex]\huge\text{\underline{\underline{Question}}}[/tex]
In the given square, a median and a diagonal cross each other. The square gets divided into four pieces. Then, find the ratio of each piece in ascending order.
[tex]\huge\text{\underline{\underline{Note}}}[/tex]
[tex]\bullet\,\text{Explanation is mandatory.}[/tex]
[tex]\bullet\,\text{\#NoCopy}[/tex]
In the given square, a median and a diagonal cross each other. The square gets divided into four pieces. Then, find the ratio of each piece in ascending order.
[tex]\huge\text{\underline{\underline{Note}}}[/tex]
[tex]\bullet\,\text{Explanation is mandatory.}[/tex]
[tex]\bullet\,\text{\#NoCopy}[/tex]
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Answer:
I'm not able to solve complete question, but still hope it might help a little.
Step-by-step explanation:
Take ∆AOE and ∆COD they both are similar by AAA.
Now use area of similar triangles property that says if we have two traingles similar such that the ratio of their sides is 1:k then the area of these triangles will be 1:k² that means square of first one.
So Area(AOE) : Area(COD) = 1:4 (cuz side ratio is 1:2)
Also take triangles AOE and ADE they are on similar base and their altitude are in ratio 1:3 so their area ratio is 1:3.
It can be said easily observed from figure that
Ar(AOE) < Ar(AOD) < Ar(DOC) < Ar(OCBE).
I don't know further this. If you know then please provide solution. I will post the same question and you may report my this ans.