Answer:
f(x)=∣2x+1∣−2∣x−1∣
Now if −∞<x≤−1/2
f(x)=−(2x+1)+2(x−1)=−3
if −1/2<x≤1
f(x)=(2x+1)+2(x−1)=4x−1
if 1<x≤∞
f(x)=(2x+1)−2(x−1)=3
Hence Range of f(x) is [−3,3]
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Answer:
f(x)=∣2x+1∣−2∣x−1∣
Now if −∞<x≤−1/2
f(x)=−(2x+1)+2(x−1)=−3
if −1/2<x≤1
f(x)=(2x+1)+2(x−1)=4x−1
if 1<x≤∞
f(x)=(2x+1)−2(x−1)=3
Hence Range of f(x) is [−3,3]