[tex]\maltese \; \pmb {\underline{\underline{\red{\frak{ \; Question \; :- }}}}}[/tex]
[tex]\longmapsto \;[/tex]Sneha bought an old car for ₹1,25,000 and Spent ₹12,000 on its repairs. After sometime, she spent ₹30,000 to modify it and sold that car to Anil at a gain of 12%. Anil sold it to Harish at a gain of 10%. How much did Harish pay for the car?
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[tex]\maltese \; \pmb {\underline{\underline{\green{\frak{ \; Note \; :- }}}}}[/tex]
[tex]\longrightarrow \; \blue{\sf{ I \; need \; full \; Explanation \; ! }}[/tex]
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[tex]\longrightarrow \; \purple{\sf{ Thanks \; in \; Advance \; !!! }}[/tex]
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Answers & Comments
Solution Through Explanation:
Sneha bought a car for Rs 1,25,000
She spent Rs 12,000 for repairs and Rs 30,000
for modifications
Total money invested = 1,25,000+12,000+30,000
= Rs 1,67,000
After all modifications and repairs, she sold it for 12% of profit to Anil
=> Money invested + (profit percent × Money invested)
i.e 167000 + (12×167000)/100
= 167000 + 20040
= 187040 rupees
Likewise,
Anil sold the car to Harsh at 10% profit
=> 187040 + (10×187040)/100
= 187040 + 18704
= 205744 rupees
Thus,
Harsh paid Rs 205744 to Anil to buy the car
Verified answer
Therefore, Harish pay ₹ 2,05,744 for the car.
Step-by-step explanation:
To Find:
According to question, we have
Cost Price of car for Sneha = 125000+12000+30000
Cost Price of car for Sneha = ₹167000
Now, she sells it to Anil at profit of 12%
Selling price of car for Sneha = 167000 + 12*167000/100
Selling price of car for Sneha = 167000 + 12*1670
Selling price of car for Sneha = ₹187040
Now, Anil sells it to Harish at profit of 10% .
Cost price of car for Anil = ₹187040
Selling Price of car for Anil = 187040 + 10*187040/100
Selling Price of car for Anil = 187040 + 18704
Selling Price of car for Anil = 205744
Therefore, Harish pay ₹ 2,05,744 for the car.