[tex] \therefore [/tex] The equation of the line is [tex] \rm{y=\frac{2}{5}x+14} [/tex]
Step-by-step explanation:
As the problem shown above, we can see the line is parallel to other line. Since there's another equation of a line, we will use there slope to find the another equation of the line. Therefore,
Given slope from the another line:
[tex] \rm{ m = \frac{2}{5}} [/tex]
Given points that passes through
[tex] \rm{(2, \ 3)} [/tex]
To find the another line, we will use the slope-point formula below:
[tex] \boxed{\bold{y-y_1=m(x-x_1)}} [/tex]
Substitute the given slope and points to the formula.
Answers & Comments
Verified answer
Answer:
Question:
Which of the following represents the equation of a line that passes through the point (2, 3) and is parallel to line [tex]y=\frac{2}{5}x-8[/tex]
Answer:
[tex]y-3=\frac{2}{5} (x-2)[/tex]
Parallel Lines and Slopes
https://www.varsitytutors.com/hotmath/hotmath_help/topics/parallel-lines-and-slopes
Step-by-step explanation:
Answer:
[tex] \therefore [/tex] The equation of the line is [tex] \rm{y=\frac{2}{5}x+14} [/tex]
Step-by-step explanation:
As the problem shown above, we can see the line is parallel to other line. Since there's another equation of a line, we will use there slope to find the another equation of the line. Therefore,
Given slope from the another line:
Given points that passes through
To find the another line, we will use the slope-point formula below:
Substitute the given slope and points to the formula.
[tex] \therefore [/tex] The equation of the line is [tex] \rm{y=\frac{2}{5}x+14} [/tex]