Answer:
In triangle PQR and triangle PSR
PQ=PS(S)
<QPR=<RPS(A)
PR=PR(S)
By S. A. S PQR=~ to PSR
By C. P. C. T QR=SR
I hope my answer helps you
Step-by-step explanation:
Given: PQ=PS
<1=<2
To Prove: Triangle PQR≅PSR
QR=SR
To Proof: In Triangle PQR and PSR
PQ=PS(given)
<1=<2(given)
PR=PR(common)
Therefore, by S-A-S RULE Triangle PQR≅PSR.
Also, by C.P.C.T.
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Answers & Comments
Answer:
In triangle PQR and triangle PSR
PQ=PS(S)
<QPR=<RPS(A)
PR=PR(S)
By S. A. S PQR=~ to PSR
By C. P. C. T QR=SR
I hope my answer helps you
Step-by-step explanation:
Given: PQ=PS
<1=<2
To Prove: Triangle PQR≅PSR
QR=SR
To Proof: In Triangle PQR and PSR
PQ=PS(given)
<1=<2(given)
PR=PR(common)
Therefore, by S-A-S RULE Triangle PQR≅PSR.
Also, by C.P.C.T.
QR=SR