raminder1
We know that sum of all angles of quadrilateral equals to 360 degree so x + x +10° + x + 20° + x + 30° = 360° 4x + 60° = 360° 4x = 360° - 60° 4x = 300° x. = 300/4 x. = 75° so first angle is 75° second angle is x + 10° = 85° third angle is x + 20° = 95° fourth angle is x + 30° = 105
regards..... :<)
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kSidd1
In the quradrilateral sum of four angles =360° Given, the frist angle =x° second angle =x+10° third angle =x+20° and fourth angle =x+30° as per the condition
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so
x + x +10° + x + 20° + x + 30° = 360°
4x + 60° = 360°
4x = 360° - 60°
4x = 300°
x. = 300/4
x. = 75°
so first angle is 75°
second angle is x + 10° = 85°
third angle is x + 20° = 95°
fourth angle is x + 30° = 105
regards..... :<)
sum of four angles =360°
Given,
the frist angle =x°
second angle =x+10°
third angle =x+20°
and fourth angle =x+30°
as per the condition
x+(x+10°)+(x+20°)+(x+30°)=360°
4x°+60°=360
4x°=360°-60°
4x=300°
x= 300/4
x=75°
therefore x = 75°
x+10=85°
x+20=95°
x+30=105°
therefore 75+85+95+105=360
hence proved