Answer:

Given: A vehicle is moving with a velocity of 19.6 meter per second whose mass is 200

kg

To Find the magnitude of force required to stop the vehicle in 10 seconds

Solution:

vehicle is moving with a velocity of 19.6 meter per second

u = 19.6 m/s

v = 0 m/s (stop/rest)

t = 10 sec

v = u + at

=> 0 19.6 + a* 10

=> a = -1.96 m/s²

force required to stop = - F

F = ma

=> Force required to stop = -ma

m = 200 kg a = -1.96 m/s²

=> Force required to stop = - 200(-1.96)

= 392 N

magnitude of force required to stop the vehicle in 10 seconds = 392 N

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the car of mass 1500 kg is moving with constant velocity 10m/s ...

Answer:

Given :-

• A vehicle is moving with velocity of 19.6 m/s, whose mass is 200 kg.

To Find :-

• What is the magnitude of force required to stop the vehicle in 10 seconds.

Solution :-

First, we have to find the acceleration :

As we know that :

[tex]\clubsuit[/tex] First Equation Of Motion Formula :

[tex]\bigstar \: \: \sf\boxed{\bold{\pink{v =\: u + at}}}\: \: \: \bigstar\\[/tex]

where,

• v = Final Velocity
• u = Initial Velocity
• a = Acceleration
• t = Time Taken

Given :

• Initial Velocity = 19.6 m/s
• Final Velocity = 0 m/s
• Time Taken = 10 seconds

According to the question by using the formula we get,

[tex]\implies \bf v =\: u + at[/tex]

[tex]\implies \sf 0 =\: 19.6 + a(10)[/tex]

[tex]\implies \sf 0 - 19.6 =\: 10a[/tex]

[tex]\implies \sf - 19.6 =\: 10a[/tex]

[tex]\implies \sf \dfrac{- 19.6}{10} =\: a[/tex]

[tex]\implies \sf - 1.96 =\: a[/tex]

[tex]\implies \sf\bold{\purple{a =\: - 1.96\: m/s^2}}\\[/tex]

Now, we have to find the magnitude of force required to stop the vehicle :

As we know that :

[tex]\clubsuit[/tex] Force Formula :

[tex]\bigstar \: \: \sf\boxed{\bold{\pink{F =\: ma}}}\: \: \: \bigstar\\[/tex]

where,

• F = Force
• m = Mass
• a = Acceleration

Given :

• Mass = 200 kg
• Acceleration = - 1.96 m/s²

According to the question by using the formula we get,

[tex]\dashrightarrow \bf F =\: ma[/tex]

[tex]\dashrightarrow \sf F =\: 200 \times (- 1.96)\\[/tex]

[tex]\dashrightarrow \sf\bold{\red{F =\: - 392\: N}}\\[/tex]

[tex]\therefore[/tex] The magnitude of force required to stop the vehicle is 392 N .

[Note :- The negetive sign means that the force is acted upon in the direction opposite to the vehicle. ]