Answer:

To find the current in this circuit, we can use Ohm's law, which states that the voltage across a resistive component (in this case, a bulb) is directly proportional to the current flowing through it. We can also use the fact that the voltage across each bulb is the same, as they are connected in series.

Using these equations, we get:

Explanation:

I = 220V / (30Ω + 30Ω + 30Ω + 30Ω) = 220V / 120Ω = 1.833 A

To find the voltage drop in each bulb, we can use Ohm's law again, remembering that the voltage across each bulb is the same:

Vdrop = I * 30Ω = 1.833 A * 30Ω = 55 V

Therefore, the voltage drop in each bulb in this circuit is 55 V, and the current in the circuit is 1.833 A.

#Credits: Me