Answer:
SI=
100
P∗R∗T
=
8000∗15∗5
=Rs.6000
Amount=8000+6000=Rs.14000
Interest =Rs.6000 , Amount=Rs.14000
6000∗12∗3
=Rs.2160
Amount=6000+2160=Rs.8160
Interest =Rs.21600 , Amount=Rs.8160
Gain6000−2160
Gain =Rs.3840
Given Principal amount P = Rs 8000
Time period T = 5 years
Rate of interest R = 15% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (8000 × 5 × 15)/100
= Rs 6000
Principal amount P = Rs 6000
Time period T = 3 years
Rate of interest R = 12% p.a.
SI = (6000 × 3 × 12)/100
= Rs 2160
Amount gained by Rakesh = Rs 6000 − Rs 2160
= Rs 3840
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Verified answer
Answer:
SI=
100
P∗R∗T
=
100
8000∗15∗5
=Rs.6000
Amount=8000+6000=Rs.14000
Interest =Rs.6000 , Amount=Rs.14000
SI=
100
P∗R∗T
=
100
6000∗12∗3
=Rs.2160
Amount=6000+2160=Rs.8160
Interest =Rs.21600 , Amount=Rs.8160
Gain6000−2160
Gain =Rs.3840
Answer:
Given Principal amount P = Rs 8000
Time period T = 5 years
Rate of interest R = 15% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (8000 × 5 × 15)/100
= Rs 6000
Principal amount P = Rs 6000
Time period T = 3 years
Rate of interest R = 12% p.a.
We know that simple interest = (P × T × R)/100
On substituting these values in above equation we get
SI = (6000 × 3 × 12)/100
= Rs 2160
Amount gained by Rakesh = Rs 6000 − Rs 2160
= Rs 3840