Let,
x + x + 2 + x + 4 = 93
3x + 6 = 93
3x = 93 - 6
3x = 87
x = 87/3
x = 29
The largest number is 33.
Let the three consecutive numbers be
x , ( x+2) , (x +4)
→ x+ (x+2 )+ (x+4 )=93
Therefore,
→3x = 93-6
→3x = 87
→x = 29
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☆ Solution ☆
Given :-
To Find :-
Step-by-Step-Explaination :-
Let,
So,
x + x + 2 + x + 4 = 93
3x + 6 = 93
3x = 93 - 6
3x = 87
x = 87/3
x = 29
Thus,
Hence,
The largest number is 33.
Verified answer
→Explanation :
Let the three consecutive numbers be
x , ( x+2) , (x +4)
→ x+ (x+2 )+ (x+4 )=93
Therefore,
→3x = 93-6
→3x = 87
→x = 29
Largest number is 29+4 = 33..