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Answer:
hey
Step-by-step explanation:
let the digits at units and tens place the given number be X and y
respectively,
thus,the number is 10y+X.
The sum of two-digit of the number is 9.
Thus,
we have,X+y=9
After interchanging the digits, the number becomes 10x+y
Also,9 times the number is equal to twice the number obtained by reversing the order of digits. Thus,
we have,
9(10y+X) = 2(10x+y)
=90y+9x=20x+2
=11x-88y=0
=11(x-8y)=0
=x-8y=0
so, we have the systems of equation
X+y=9 , x-8y=0
here, X and y are unknowns we have, to solve the above systems of equations for X and y
substituting X=8y from the second equation to first equation
we get,
=8y+y=9
=9y=9
y=9/9
y=1
substituting the value of y in the second equation.
x-8×1=0
x-8=0
X=8
Hence, the number is 10×1+8=18
thanks
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Answers & Comments
yes I am there on snap chat
Verified answer
Answer:
hey
Step-by-step explanation:
let the digits at units and tens place the given number be X and y
respectively,
thus,the number is 10y+X.
The sum of two-digit of the number is 9.
Thus,
we have,X+y=9
After interchanging the digits, the number becomes 10x+y
Also,9 times the number is equal to twice the number obtained by reversing the order of digits. Thus,
we have,
9(10y+X) = 2(10x+y)
=90y+9x=20x+2
=11x-88y=0
=11(x-8y)=0
=x-8y=0
so, we have the systems of equation
X+y=9 , x-8y=0
here, X and y are unknowns we have, to solve the above systems of equations for X and y
substituting X=8y from the second equation to first equation
we get,
=8y+y=9
=9y=9
y=9/9
y=1
substituting the value of y in the second equation.
we have,
x-8×1=0
x-8=0
X=8
Hence, the number is 10×1+8=18
thanks