Answer:
Step-by-step explanation:
Given, the sum of the digits of a two-digit number is 11. The given number is less than the number obtained by interchanging the digits by 9. We have to find the number. Therefore, the required number is 56.
Given: Sum of digits of a 2 digit number is 11 . Actual number is less than the number obtained by interchanging the actual digits by 9.
Solution : Let y be at ones place and x be at tens place
The sum of the digits of a two digit number is x + y = 11
x + y = 11 ….. (1)
Number we obtain on interchanging the digits of actual no.
(10×y+x) - (10×x+y)= 9 …..(2)
10×y+x - 10×x -y =9
9×y - 9×x=9
y-x = 1 …..(3)
using (1) and (3) we get
x+ y =11
-x + y=1
2×y=12
y= 6
putting the value of y in equation (1) we get,
x=5
y=6, x= 5
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Answer:
Step-by-step explanation:
Given, the sum of the digits of a two-digit number is 11. The given number is less than the number obtained by interchanging the digits by 9. We have to find the number. Therefore, the required number is 56.
Answer:
Step-by-step explanation:
Given: Sum of digits of a 2 digit number is 11 . Actual number is less than the number obtained by interchanging the actual digits by 9.
Solution : Let y be at ones place and x be at tens place
The sum of the digits of a two digit number is x + y = 11
x + y = 11 ….. (1)
Number we obtain on interchanging the digits of actual no.
(10×y+x) - (10×x+y)= 9 …..(2)
10×y+x - 10×x -y =9
9×y - 9×x=9
y-x = 1 …..(3)
using (1) and (3) we get
x+ y =11
-x + y=1
2×y=12
y= 6
putting the value of y in equation (1) we get,
x=5
y=6, x= 5