Verified answer

Answer:

Explanation:

Let side of square 1 be x metres

Perimeter of square 1 = 4Side = 4x

Now, it is given that

Difference of perimeter of squares is 24 m

Perimeter of square 1 - Perimeter of square 2 = 24

4x - perimeter of square 2 = 24

4x - 24 = perimeter of square 2

Perimeter of square 2 = 4x - 24

Now,

Perimeter of square 2 = 4x - 24

4* (Side of square 2 )=4x-24

Side of square 2= 4x-24 4 = 4(x-6) 4 =x-6

Hence,

Side of square 1 is x

& Side of square 2 is x - 6

Also, given that

Sum of area of square is 468m ^ 2

Area of square 1 + A of square 2 = 468

(Side of square 1)^ 2 +(s of square 2)^ 2 =468

x ^ 2 + (x - 6) ^ 2 = 468

x ^ 2 + x ^ 2 - 2x * 6 + 6 ^ 2 = 468

x ^ 2 + x ^ 2 - 12x + 36 = 468

x ^ 2 + x ^ 2 - 12x + 36 - 468 = 0

2x ^ 2 - 12x - 432 = 0

Dividing both sides by 2

(2x ^ 2 - 12x - 432)/2 = 0/2

x ^ 2 - 6x - 216 = 0

Comparing equation with a * x ^ 2 + bx + c = 0 Here a = 1 , b = - 6 c = - 216

We know that

D = b ^ 2 - 4ac

D = (- 6) ^ 2 - 4 * 1 * (- 216)

D = 36 + 4 * 216

D = 36 + 864

D=90(

So, the roots to equation are

x = (- b plus/minus sqrt(D))/(2a)

Putting values

x = (- (- 6) plus/minus sqrt(900))/(2 * 1)

x = (- (- 6) plus/minus sqrt(900))/(2 * 1)

x = (6 plus/minus sqrt(900))/2

x = (6 plus/minus sqrt(9 * 100))/2

x = (6 plus/minus sqrt(3 ^ 2 * 10 ^ 2))/2

x = (6 plus/minus sqrt(3 ^ 2) * sqrt(10 ^ 2))/2

x = (6 plus/minus 3 * 10)/2

x = (6 plus/minus 30)/2

Solving

x = (6 + 30)/2 x = 18

x = 36/2

x = (6 - 30)/2

x = - 24/2

x = - 12

So, x=18\&x=-12

Since x is side of square and x cannot be negative

So, x = 18 is the solution

:: Side of square 1 = x = 18m

& Side of square 2=x-6=18-6=12 m

I don't know if it is correct or not it is solved by my dad.

Answer:

you're in 10th after all we're of same age..I'm donkey when it comes to math..but 12 and 18 are correct answers..I think