Answer:Group the digits in pairs from the right and alternately add and subtract the two digit numbers formed also from the right. Repeat until you get zero in which case it's divisible by 101, or you get a nonzero number between 1 and 100, which would be the remainder were you to divide. If all you care about is divisibilty you can flip signs at any stage.
Answer:Group the digits in pairs from the right and alternately add and subtract the two digit numbers formed also from the right. Repeat until you get zero in which case it's divisible by 101, or you get a nonzero number between 1 and 100, which would be the remainder were you to divide. If all you care about is divisibilty you can flip signs at any stage.Example. I'll do it for 2370190634
Answer:Group the digits in pairs from the right and alternately add and subtract the two digit numbers formed also from the right. Repeat until you get zero in which case it's divisible by 101, or you get a nonzero number between 1 and 100, which would be the remainder were you to divide. If all you care about is divisibilty you can flip signs at any stage.Example. I'll do it for 2370190634Grouping by pairs of digits it's 23, 70, 19, 06, 34.
Answer:Group the digits in pairs from the right and alternately add and subtract the two digit numbers formed also from the right. Repeat until you get zero in which case it's divisible by 101, or you get a nonzero number between 1 and 100, which would be the remainder were you to divide. If all you care about is divisibilty you can flip signs at any stage.Example. I'll do it for 2370190634Grouping by pairs of digits it's 23, 70, 19, 06, 34.Alternated sums and differences 34 - 6+ 19-70 + 23 is the same as 34 +19 +23 - (6 +70) = 76-76 = 0.
Answer:Group the digits in pairs from the right and alternately add and subtract the two digit numbers formed also from the right. Repeat until you get zero in which case it's divisible by 101, or you get a nonzero number between 1 and 100, which would be the remainder were you to divide. If all you care about is divisibilty you can flip signs at any stage.Example. I'll do it for 2370190634Grouping by pairs of digits it's 23, 70, 19, 06, 34.Alternated sums and differences 34 - 6+ 19-70 + 23 is the same as 34 +19 +23 - (6 +70) = 76-76 = 0.So this is divisible by 101.
Answer:Group the digits in pairs from the right and alternately add and subtract the two digit numbers formed also from the right. Repeat until you get zero in which case it's divisible by 101, or you get a nonzero number between 1 and 100, which would be the remainder were you to divide. If all you care about is divisibilty you can flip signs at any stage.Example. I'll do it for 2370190634Grouping by pairs of digits it's 23, 70, 19, 06, 34.Alternated sums and differences 34 - 6+ 19-70 + 23 is the same as 34 +19 +23 - (6 +70) = 76-76 = 0.So this is divisible by 101.Step-by-step explanation:
Answers & Comments
Step-by-step explanation:
when we multiply both the numbers we can get a number that is divisible by the both numbers i.e.
99×101 = 9999
9999÷101=99 and 9999÷99=101
please vote brainliest
Answer:
Answer:Group the digits in pairs from the right and alternately add and subtract the two digit numbers formed also from the right. Repeat until you get zero in which case it's divisible by 101, or you get a nonzero number between 1 and 100, which would be the remainder were you to divide. If all you care about is divisibilty you can flip signs at any stage.
Answer:Group the digits in pairs from the right and alternately add and subtract the two digit numbers formed also from the right. Repeat until you get zero in which case it's divisible by 101, or you get a nonzero number between 1 and 100, which would be the remainder were you to divide. If all you care about is divisibilty you can flip signs at any stage.Example. I'll do it for 2370190634
Answer:Group the digits in pairs from the right and alternately add and subtract the two digit numbers formed also from the right. Repeat until you get zero in which case it's divisible by 101, or you get a nonzero number between 1 and 100, which would be the remainder were you to divide. If all you care about is divisibilty you can flip signs at any stage.Example. I'll do it for 2370190634Grouping by pairs of digits it's 23, 70, 19, 06, 34.
Answer:Group the digits in pairs from the right and alternately add and subtract the two digit numbers formed also from the right. Repeat until you get zero in which case it's divisible by 101, or you get a nonzero number between 1 and 100, which would be the remainder were you to divide. If all you care about is divisibilty you can flip signs at any stage.Example. I'll do it for 2370190634Grouping by pairs of digits it's 23, 70, 19, 06, 34.Alternated sums and differences 34 - 6+ 19-70 + 23 is the same as 34 +19 +23 - (6 +70) = 76-76 = 0.
Answer:Group the digits in pairs from the right and alternately add and subtract the two digit numbers formed also from the right. Repeat until you get zero in which case it's divisible by 101, or you get a nonzero number between 1 and 100, which would be the remainder were you to divide. If all you care about is divisibilty you can flip signs at any stage.Example. I'll do it for 2370190634Grouping by pairs of digits it's 23, 70, 19, 06, 34.Alternated sums and differences 34 - 6+ 19-70 + 23 is the same as 34 +19 +23 - (6 +70) = 76-76 = 0.So this is divisible by 101.
Answer:Group the digits in pairs from the right and alternately add and subtract the two digit numbers formed also from the right. Repeat until you get zero in which case it's divisible by 101, or you get a nonzero number between 1 and 100, which would be the remainder were you to divide. If all you care about is divisibilty you can flip signs at any stage.Example. I'll do it for 2370190634Grouping by pairs of digits it's 23, 70, 19, 06, 34.Alternated sums and differences 34 - 6+ 19-70 + 23 is the same as 34 +19 +23 - (6 +70) = 76-76 = 0.So this is divisible by 101.Step-by-step explanation:
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