Answer:
f(x) = √2x - 4
Domain: x ∈ [2, +∞⟩
≈ x ≥ 2
Range: f(x) ∈ [0, +∞⟩
y = √2, when x = 3
y = 2, when x = 4
y = √6, when x = 5
y = √8, when x = 6
y = √10, when x = 7
To find the inverse, substitute f(x) as y.
y = √2x - 4
Interchange the variables.
x = √2y - 4
Swap the sides.
√2y - 4 = x
Square both sides of the equation.
2y - 4 = x²
Move -4 to the right-hand side and change its sign.
2y = x² + 4
Divide both sides by 2.
y = ½x² + 2
Substitute y as f^-1(x).
f^-1(x) = ½x² + 2
Inverse: ½x² + 2
Domain: x ∈ R
Range: f^-1(x) ∈ [2, +∞⟩
y = 13/2, when x = 3
y = 10, when x = 4
y = 29/2, when x = 5
y = 20, when x = 6
y = 53/2, when x = 7
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Answers & Comments
Answer:
f(x) = √2x - 4
Domain: x ∈ [2, +∞⟩
≈ x ≥ 2
Range: f(x) ∈ [0, +∞⟩
y = √2, when x = 3
y = 2, when x = 4
y = √6, when x = 5
y = √8, when x = 6
y = √10, when x = 7
To find the inverse, substitute f(x) as y.
y = √2x - 4
Interchange the variables.
x = √2y - 4
Swap the sides.
√2y - 4 = x
Square both sides of the equation.
2y - 4 = x²
Move -4 to the right-hand side and change its sign.
2y = x² + 4
Divide both sides by 2.
y = ½x² + 2
Substitute y as f^-1(x).
f^-1(x) = ½x² + 2
Inverse: ½x² + 2
Domain: x ∈ R
Range: f^-1(x) ∈ [2, +∞⟩
y = 13/2, when x = 3
y = 10, when x = 4
y = 29/2, when x = 5
y = 20, when x = 6
y = 53/2, when x = 7