Answer:

To solve this problem, we can use the equations of motion to determine the time of flight and the height of the building. Let's assume the acceleration due to gravity is approximately 9.8 m/s².

First, we need to find the time of flight. Since the ball is thrown horizontally, its initial vertical velocity is 0 m/s.

Using the equation for horizontal motion:

distance = velocity × time,

where distance is the horizontal distance traveled by the ball.

Given:

velocity = 5 m/s

distance = 3.5 m

Rearranging the equation:

time = distance / velocity

Substituting the values:

time = 3.5 m / 5 m/s

time ≈ 0.7 seconds

Now that we know the time of flight, we can determine the height of the building using the equation for vertical motion:

height = initial vertical velocity × time + (1/2) × acceleration due to gravity × time²

Since the initial vertical velocity is 0 m/s, the equation simplifies to:

height = (1/2) × acceleration due to gravity × time²

Substituting the values:

height = (1/2) × 9.8 m/s² × (0.7 s)²

height ≈ 2.43 meters

Therefore, the height of the building is approximately 2.43 meters.

Explanation:

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