Answer:
AB || CD
=> angle ABF = angle BFC ( alternative angle )
=>angle BFC = 120°
=> angle CFE = 180° - 120°
= 60°
angle DCE = 130°
=> angle FCE = 180° - 130°
= 50°
Now , in ∆ CEF ,
CEF + FCE + CFE = 180°
=> x + FCE + CFE = 180°
=> x + 50° + 60° = 180°
=> x + 110° = 180°
=> x = 70°
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Answer:
AB || CD
=> angle ABF = angle BFC ( alternative angle )
=>angle BFC = 120°
=> angle CFE = 180° - 120°
= 60°
angle DCE = 130°
=> angle FCE = 180° - 130°
= 50°
Now , in ∆ CEF ,
CEF + FCE + CFE = 180°
=> x + FCE + CFE = 180°
=> x + 50° + 60° = 180°
=> x + 110° = 180°
=> x = 70°