A milkman has 5 1/2 litrrs of milk in his can. He gives 7/8 litre to Renuka, Mansi and Niru each. Then he gives 1 1/2 litre of milk to vijya. How much milk is left in the can now.
The milkman started with 11/2 liters of milk. He gave 7/8 liters to Renuka, Mansi, and Niru each, which is a total of 7/8 + 7/8 + 7/8 = 21/8 liters. Then he gave 3/2 liters to Vijya.
To find out how much milk is left in the can, we need to subtract the amount given from the starting amount.
Starting amount: 11/2 liters
Amount given: 21/8 + 3/2 liters
To subtract fractions, we need to have a common denominator. Let's convert everything to eighths:
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Answer:
A milkman has 5 1/2 litrrs of milk in his can. He gives 7/8 litre to Renuka, Mansi and Niru each. Then he gives 1 1/2 litre of milk to vijya. How much milk is left in the can now.
The milkman started with 11/2 liters of milk. He gave 7/8 liters to Renuka, Mansi, and Niru each, which is a total of 7/8 + 7/8 + 7/8 = 21/8 liters. Then he gave 3/2 liters to Vijya.
To find out how much milk is left in the can, we need to subtract the amount given from the starting amount.
Starting amount: 11/2 liters
Amount given: 21/8 + 3/2 liters
To subtract fractions, we need to have a common denominator. Let's convert everything to eighths:
Starting amount: 11/2 * 4/4 = 44/8 liters
Amount given: 21/8 + 3/2 * 4/4 = 21/8 + 12/8 = 33/8 liters
Now, let's subtract the amount given from the starting amount:
44/8 - 33/8 = 11/8 liters
So, there is 11/8 liters of milk left in the can.
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Verified answer
[tex]Milkmen \: has \: =5 \frac{1}{2} \: litre \\ [/tex]
[tex]Given \: to \: Renuika ,musni \: \\ and \: Niru \: \frac{7}{8} \\ \\ = \frac{11}{2} - \frac{7}{8} \\ \\ = \frac{44 - 7}{8} \\ \\ = \frac{37}{8} \: ltr[/tex]
[tex]To \: Vijaya \: also \: =1 \frac{1}{2} \\ \\ Left = \frac{37}{8} - \frac{3}{2} \\ \\ = \frac{37 - 12}{8} \\ \\ = \frac{25}{8} \: ltr[/tex]