Sandeepbhau borrowed 120000 rupees from a bank for 4 years at the rate of 8 ½ p.c.p.a. for his son's education.

To Find: The total amount he returned to the bank at the end of that period.

____

As we know that:

\dag \; \underline{\boxed{\frak{\orange{Total \; Intrest \; I = \dfrac{P \times T \times R}{100}}}}}†

TotalIntrestI=

100

P×T×R

Therefore,

\implies \sf{Total \; Interest = \dfrac{P \times R \times T}{100} }⟹TotalInterest=

100

P×R×T

\implies \sf{Total \; Interest = \dfrac{120 \cancel{0} \cancel{0} \cancel{0} \times 85 \times 4}{1\cancel{0} \cancel{0} \times 1 \cancel{0}} }⟹TotalInterest=

1

0

0

×1

0

120

0

0

0

×85×4

\implies \sf{Total \; Interest = 120 \times 85 \times 4 }⟹TotalInterest=120×85×4

\implies \underline{\boxed{\sf{\purple{Total \; Interest = 40800}}}}⟹

TotalInterest=40800

As we know that,

\dag \; \underline{\boxed{\frak{\orange{ Principal +Interest = Amount }}}}†

Principal+Interest=Amount

Therefore,

\implies \sf{120000 + 40800 }⟹120000+40800

\implies \underline{\boxed{\sf{\purple{160800 \; rupees }}}}⟹

160800rupees

★ Final Answer:

⇒ The total amount returned to the bank is ₹ 160800.

Extra interest =13483.20−13440=Rs.43.20