A ball is dropped from top of a building. It accelerates uniformly at a rate of 10m/s2
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Find the height of the building if the ball hits the ground with a speed of 20m/s.
please explain the answer
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Find the height of the building if the ball hits the ground with a speed of 20m/s.
please explain the answer
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Explanation:
acceleration,a=10m/s^2,
final velocity,v=20m/s,
initial velocity,u=0 m/s, #it is at rest in top.
now using the formula,v^2-u^2=2aS.
where, S=height of the building.
(v^2-u^2)/2a=S,
S={(20)^2-(0)^2}/2*10,
S=(400/20)meters,
S=20 meters.
therefore,height of the building=20 meters.
Hope this helps...
Answer:
meri bhi vohi problem hai