[tex]________________________________________[/tex]
[tex] \tt \blue {PROBLEM:}[/tex]5 + 9x = 2x²
→ 5 + 9x = 2x² = [tex] \big \green{x _{1} = - \frac{1}{2},x_{2} = 5}[/tex]
=====================================
The 2x+1=0 solve the equation for x
→ [tex] \red \big {x = - \frac{ 1}{2} }[/tex]
And then the x-5=0 solve too the equation for x
→ [tex] \red \big {x = 5}[/tex]
This [tex]\pink \big {x = - \frac{ 1}{2} }[/tex] and [tex]\pink \big {x = - \frac{ 1}{2} }[/tex] has a 2 solutions.
→ The answer is [tex] \boxed{x _{1} = - \frac{1}{2},x_{2} = 5}[/tex]
#CARRY ON LEARNING <3
#Nasa picture po yung explanation ko,Rude words kasi.
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✏️QUADRATIC EQUATION
[tex]________________________________________[/tex]
[tex] \tt \blue {PROBLEM:}[/tex]5 + 9x = 2x²
→ 5 + 9x = 2x² = [tex] \big \green{x _{1} = - \frac{1}{2},x_{2} = 5}[/tex]
=====================================
The 2x+1=0 solve the equation for x
→ [tex] \red \big {x = - \frac{ 1}{2} }[/tex]
And then the x-5=0 solve too the equation for x
→ [tex] \red \big {x = 5}[/tex]
This [tex]\pink \big {x = - \frac{ 1}{2} }[/tex] and [tex]\pink \big {x = - \frac{ 1}{2} }[/tex] has a 2 solutions.
→ The answer is [tex] \boxed{x _{1} = - \frac{1}{2},x_{2} = 5}[/tex]
[tex]________________________________________[/tex]
#CARRY ON LEARNING <3
#Nasa picture po yung explanation ko,Rude words kasi.