Some people share a box of chocolates equally. Each person gets 6 chocolates. Three times as many people share an identical box of chocolates. Find how many chocolates each person gets.
Explanation:If each person gets 6 chocolates in the first scenario, and three times as many people share an identical box in the second scenario, we can calculate the number of chocolates each person gets in the second scenario.
Let x be the number of people in the second scenario.
In the first scenario, the total number of chocolates is 6 chocolates/person * x people = 6x.
In the second scenario, three times as many people share the chocolates, so the total number of chocolates is 6 chocolates/person * 3x people = 18x.
Now, we can set up an equation:
6
�
=
18
�
6x=18x
Solving for x:
12
�
=
0
12x=0
�
=
0
x=0
However, since the number of people cannot be zero, there might be an issue with the information provided. If there were a different number of chocolates or if more context were given, we might be able to find a solution. As it stands, with the information provided, it seems there is a discrepancy in the problem.
Answers & Comments
Answer:
Explanation:If each person gets 6 chocolates in the first scenario, and three times as many people share an identical box in the second scenario, we can calculate the number of chocolates each person gets in the second scenario.
Let x be the number of people in the second scenario.
In the first scenario, the total number of chocolates is 6 chocolates/person * x people = 6x.
In the second scenario, three times as many people share the chocolates, so the total number of chocolates is 6 chocolates/person * 3x people = 18x.
Now, we can set up an equation:
6
�
=
18
�
6x=18x
Solving for x:
12
�
=
0
12x=0
�
=
0
x=0
However, since the number of people cannot be zero, there might be an issue with the information provided. If there were a different number of chocolates or if more context were given, we might be able to find a solution. As it stands, with the information provided, it seems there is a discrepancy in the problem.